5y^2-35y-40=0

Solution for 5y^2-35y-40=0 equation:

5y^2-35y-40=0

a = 5; b = -35; c = -40;
Δ = b2-4ac
Δ = -352-4·5·(-40)
Δ = 2025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2025}=45$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-35)-45}{2*5}=\frac{-10}{10}
=-1
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-35)+45}{2*5}=\frac{80}{10}
=8
$